Two ships leave port at the same time, Ship X is heading due north and Ship Y is heading due east. Eleven hours later they are 550 miles apart. If the Ship X had
travels 440 miles from the port, how many miles will Ship Y travel?

330 miles

Step-by-step explanation:

You can solve it using the Pythagoras theorem.

x=Distance from the port to ship Y

550²=440² + x²

x²=550²-440²

x²=302,500-193,600

x²=108,900

x=330

Hope it helps.

I have attached a diagram as well though it might not be really clear.Hope it helps.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

54.864 meters

step-by-step explanation: