A ball is thrown from a height of 32 meters with an initial downward velocity of 2/ms. The ball's height h (in meters) after t seconds is given by the following. =h−32−2t5t2 How long after the ball is thrown does it hit the ground?

0=65-10t-5t^2

now what you want to do is multiply a and c

-5(t^2+2t-13)

Now just find the zeros

the answer is 0.3175 hope that you ^w^

also you might actually want to put this picture up if you want people to solve it luckily i remember this question

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42