Solve the system or linear equations

37. {-1, -1}.

Step-by-step explanation:

I'll solve the first one . The other can be solved in a similar way. We can use the method of elimination.

x1 - x2 = 0

3x1 - 2x2 = -1

We can multiply the first equation by -2. We then have an equation containing + 2x2 so when we add this to the second equation the 2x2 will be eliminated

So the first equation becomes:

-2x1 + 2x2 = 0     Bring down the second equation:

3x1 - 2x2 = -1       Now adding, we get:

x1 + 0 = -1

so x1 = -1.

Now we substitute this value of x1 in the original first equation:

-1 - x2 = 0

-1 = x2

x2 = -1.

So the solution set is {-1, -1}.

If there are more than 2 equations you can use a combination of substitutions and eliminations.

go on the tube you might find some information there

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?