Mathematics
Mathematics, 11.09.2021 06:10, howell62

'stackrel(harr)(AB)' is parallel to 'stackrel(harr) (CD)'. `bar(AC) and "bar(BD) are perpendicular
to 'stackrel(harr)(AB)' and 'stackrel(harr)(CD)' . What is
the relationship between bar(AC) and "bar(BD) ?

ANSWER DOWN BELOW
D: β€˜ AB β€˜ = β€˜ CD β€˜


'stackrel(harr)(AB)' is parallel to 'stackrel(harr)
 

(CD)'. `bar(AC) and bar(BD) are perpendicul

answer
Answers: 1

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'stackrel(harr)(AB)' is parallel to 'stackrel(harr) (CD)'. `bar(AC) and "bar(BD) are perpendicula...

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