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Mathematics, 11.09.2021 06:10, howell62
'stackrel(harr)(AB)' is parallel to 'stackrel(harr)
(CD)'. `bar(AC) and "bar(BD) are perpendicular
to 'stackrel(harr)(AB)' and 'stackrel(harr)(CD)' . What is
the relationship between bar(AC) and "bar(BD) ?
ANSWER DOWN BELOW
D: β AB β = β CD β
![answer](/tpl/images/cats/otvet.png)
Answers: 1
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'stackrel(harr)(AB)' is parallel to 'stackrel(harr)
(CD)'. `bar(AC) and "bar(BD) are perpendicula...
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