![\dfrac{\sqrt[3]{7}}{\sqrt[5]{7}} = \dfrac{7^{1/3}}{7^{1/5}}](/tpl/images/2461/0676/942e6.png)
, so that
![\dfrac{\sqrt[3]{7}}{\sqrt[5]{7}} = 7^{2/15}](/tpl/images/2461/0676/4cdd9.png)
Help? Very confused math is not my subject.
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Answers: 2
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