Hugh has to earn at least $400 to meet his fundraising goal he only has 100 books that he plans to sell at $8 each. Which inequality shows the number of books, x, Hugh can sell at his goal? (9th-grade Algebra 1)

The revenue in the problem is equal to $400 that is to be made out of 100 books selling at $8 each. The minimum number of books he has to seel is $400/$8 per book of 50 books. The maximum number is 100 books. Hence the answer to this problem is 50 ≤ x ≤ 100.

Step-by-step explanation:

The revenue in the problem is equal to $400 that is to be made out of 100 books selling at $8 each. The minimum number of books he has to seel is $400/$8 per book of 50 books. The maximum number is 100 books. Hence the answer to this problem is 50 ≤ x ≤ 100.

50=33x+22

step-by-step explanation:

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