o be eligible for a parking pass on a college campus, a student must live at least 1 mile from the campus center. A picture shows x y plane, with a circle of center at the origin with a radius of 1 mile. The center of the circle is labeled campus center. A line parallel to the y-axis on the left side and at a distance of 2 miles from the center is labeled Main Street. A point on the x-axis and on the right side, at a distance of 5 miles is labeled College Drive. A line from a point on main street that is 1 mile from the x axis to the x axis at college drive is labeled oak lane. a. Write equations the represent the circle and Oak Lane. Circle: Oak Lane: Question 2 b. Solve the system that consists of the equations in part (a). ( , ) and ( , ) Question 3 c. For what length of Oak Lane are students not eligible for a parking pass

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube

one way is to plot 2 points and connect them which is what the answer choices seem to be doing

it seems to be using the y intercept and the slope

y=mx+b, m=slope, b=y-intercept (where the line hits the y axis)

slope=rise/run

y-intercept is where the line croses the y axis which is the y value where x=0

you seem to have given the wrong slope (you didn't put a number in front of te x, it should be 2/3 or 3/2 looking at the answer options)

y=? x-1

m=? because of your fault

b=-1

so it has a slope of ? and y intercept of -1, meaning it pases through (0,-1)

so draw point (0,-1) (so answer is one of the first 2 option)

if slope is 2/3, then go up 2 and right 3 then draw line through those 2 points

if slope is 3/2, then go up 3 and right 2 then draw line through those 2 points

that would be a prism, if not right, feel free to correct me