Consider the following triangle: Part A:find the perimeter of the triangle:
Options__
1) 72^1/2+32^1/2+2.16^1/3
2) 72^1/2+32^1/2+32^1/3
3) 104^1/2+2.16^1/3
Part B: Ronnie correctly rewrote the perimeter using radicals. Which expression did he use?
1) √32+ √72+3^ √16
2) √32+ √72+ √16
3) √32+ √72+3^ √32
4) √32+ √72+2 3^ √16

answer are

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

536

step-by-step explanation:

the answer is simply just 6n add the two together as they have an n