Can someone help me please?!?!

Your answer will be x= 3(c−k).

I hope this helps :)

A. x = (c-k)/3

Step-by-step explanation:

3x+k=c

Subtact k

3x-c-k

Divide by three

x = (c-k)/3

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: