Consider the graphed function.
what are the domain and the range of this function ​

Step-by-step explanation:

Domain

The graph shows the points in which the domain is located. To find the Domain, go to the point in the x-axis (the horizontal line) and note the number where the point lies. For this question, the Domain lies in -5 and 1. Once you've found that, it's time to write it down. To do that you'll need to write the number at the most left before the one at the right. So it should be -5 less than/equal to X. Now since the point at the right is an "open-circle", x is less than the number at the most right. Not the same as a closed circle. So at the end of the process, you should have gotten -5 less than/equal to X less than 1 = .

Range

The graph shows the points in which the range is located. To find the Range, go to the point in the y-axis (the vertical line) and note the number where the point lies. For this question, the Range lies in -4 and 7. Once you've found that, it's time to write it down. To do that you'll need to write the number at the most left before the one at the right. So it should be -4 less than/equal to X. Now since the point at the right is an "open-circle", x is less than the number at the most right. Not the same as a closed circle. So at the end of the process, you should have gotten -4 less than/equal to X less than 7 = .

the red lines denote the population of the bacteria after 35 hours. that would be 2,409.24. the y-intercept is the blue line which is 800 because that is the starting point. the equation used to make the graph is 800(1.032)^h, where h is the number of hours.

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v