PLEASE HELP AND FAST PLEASE 2. To help evaluate the original report, draw a normal curve for the data Marjin-O'Heara
collected. Include the values of the mean and the first three standard deviations in your
sketch. (4 points: 1 point for the curve, 3 points for correct critical values)
1
3. The client was hoping for a likability score of at least 5.2. Use your sample mean and
standard deviation identified in the answer to question 1 to complete the following table for the
margins of error and confidence intervals at different confidence levels. Note: No further
calculations are needed for the sample mean. (6 points: 2 points for each completed row)
Margin of error
Confidence
level
Center of Lower
confidence boundary of
interval
confidence
(sample mean) interval
Upper
boundary of
confidence
interval
68%
95%
99.7%

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

gmt is 4 hrs ahead of edt so just add four hours to 1: 14: 20 (minutes and seconds stay the same)

gmt is 5: 14: 20

hope this !

~just a girl in love with shawn mendes

i would say true? if the unit was informational and it "refreshed your understanding", then true.