Under certain conditions, 100 percent of the cells in
fungus A reproduce in 24
hours. The number of cells of
fungus A doubles once each
day.
Day 1 = 10,000 cells
Day 2 = 20,000 cells
Day 3 = 40,000 cells
Day 4 = 80,000 cells
When an antibiotic is added
to the fungus, the growth is
reduced by 50 percent. Only
half the cells reproduce each
day.
Day 2 = 15,000 cells
Day 3 = 22,500 cells
Day 4 = 33,750 cells
7. Calculate Without an
antibiotic, how many cells of
fungus A would there be on
day 6?

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

step-by-step explanation: