Compute the discriminant. Then determine the number and type of solutions for the given equation. x 2 + 7x + 6 = 0

-73; two complex imaginary solutions

0; one real solution

25; two unequal real solutions

Step-by-step explanation:

It's two unequal real solutions.

a = 1

b = 7

c = 6

discriminate = sqrt(7^2 - 4*1*6)

discriminate = sqrt(49 - 24)

discriminate = sqrt(25)

discriminate = 5

Now you cannot determine what this means unless you put it in the quadratic formula

x = (-7 +/- 5)/2

x = (- 7 + 5) / 2

x =  - 2/2 = - 1

x = (-7 - 5)/2

x = -12/2

x = - 6

You see that you have two unequal reals.