Is it possible for a rectangle to have rational side lengths and an irrational area?

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)