Mathematics, 02.09.2021 05:50, sdfhghjg

Bài 2: Tìm x, biếta) 6x (3x + 5) –2x (9x –2) = 17b) 2x(3x -1) –3x(2x + 11) -70 = 0c) (3x –1)(2x + 7) –(x + 1)(6x –5) = 16d) (2x + 3)2–(2x + 1)(2x –1) = 22e) (4x + 3) (4x –3) –(4x –5)2= 46f) 25x2–9 = 0Bài 3: Giải các phương trình sau:a) xxx2( 2) –( –3)( 3) 6−+ =b) xxx2( 3) (4 )(4– ) 10+ + +=c) xxx2( 4) (1– )(1 ) 7+ ++ =d) xxx2( –4) –( –2)( 2) 6+=e) xxx24( –3) –(2 –1)(2 1) 10+=f) xxx225( 3) (1–5 )(1 5 ) 8+ ++ =g) xxx29( 1) –(3 –2)(3 2) 10++ =h) xxx24( –1) (2 –1)(2 1) 3−++ = −Bài 4:Tìm x, biếta) (x + 8)(x + 6) -x2= 104b) 6x2-(2x -3)(3x + 2) –1 = 0c) (x + 4)2–(x + 1)(x -1) = 16d) (10x + 9)x –(5x -1)(2x + 3) = 8e) (2x -1)2+ (x + 3)2–5(x + 7)(x –7) = 0f) x(x + 1) (x + 6) –x3= 5x

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Bài 2: Tìm x, biếta) 6x (3x + 5) –2x (9x –2) = 17b) 2x(3x -1) –3x(2x + 11) -70 = 0c) (3x –1)(2x + 7)...