Let f be the function defined by f(x)=((ax2+bx+2)/(2x2-8)), where a and b are constants. The graph of f has a horizontal asymptote at y=3, and a removable discontinuity at x=2. 1) Given the above information, find the values of a and b. (Show work)

2) Find limit as x approaches 2 of f(x). (Show work)

3) At what values of x does f have a discontinuity due to a vertical asymptote? Show the behaviour on the left and right side of this asymptote using limits.

the image of (6, 9) under a dilation is (4, 6). the scale factor is

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)

6 cars because if you have 8 and subtract 2 youll have 6 left over