If 9th term ofap is 99 and 99th term is 9 which term is zero
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13 term is zero

Step-by-step explanation:

please give me brainlest

108 th term is zero

Step-by-step explanation:

The nth term of an AP is

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₉ = 99 and a₉₉ = 9 then

a₁ + 8d = 99 → (1)

a₁ + 98d = 9 → (2)

Subtract (1) from (2) term by term to eliminate a₁

0 + 90d = - 90

90d = - 90 ( divide both sides by 90 )

d = - 1

Substitute d = - 1 into (1) for value of a₁

a₁ + 8(- 1) = 99

a₁ - 8 = 99 ( add 8 to both sides )

a₁ = 107

Then

107 - (n - 1) = 0

107 - n + 1 = 0

- n + 108 = 0 ( subtract 108 from both sides )

- n = - 108 ( multiply both sides by - 1 )

n = 108

The 108th term is zero

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.

7/2

(decimal: 3.5)

welcome ; )

step-by-step explanation: