How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 10% antifreeze to get a mixture that is 50% antifreeze? Use the six-step method.
You need gallons.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

17

step-by-step explanation:

51/3=17

thus 17 is your answer.