What is an equation of the line that passes through the point (3,-1)(3,−1) and is parallel to the line 5x+3y=65x+3y=6?

Step-by-step explanation:

5x+3y = 6

5x = 6 - 3y

5x = 3(2-y)

5x/3 = 2 - y

y = 2 - (5x/3)

slope = x coefficient.

= - 5/3

Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

new slope = 3/5

the equation formula

y = mx + b

m = new slope = 3/5

y = (3x/5) + b

From the point given (3 , -1 )

x = 3.

y = -1

-1 = (9/5) + b

b =( -5/5) - (9/5)

b = - 14 / 5

3

step-by-step explanation:

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places