Solve the equation below. A.
x = -2
B.
x = 2
C.
x = 0, -2
D.
x = 0, 2

Suppose that f(0) = −3 and f '(x) ≤ 8 for all values of x. how large can f(4) possibly be? solution we are given that f is differentiable (and therefore continuous) everywhere. in particular, we can apply the mean value theorem on the interval [0, 4] . there exists a number c such that

What is the product? (x2+3y+7) [yy+1)

5,600 x 10^3 = a) 560 b) 5,000,600 c) 5,600,000 d) 56,000