Find the standard equation of the circle which satisfies the following criteria: center (2, 3), passes through (5, -1)

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

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step-by-step explanation:

it me < 3

hi there, i would be interested to you with your test, may you add the questions and answer options.

- : )