Let AB be a diameter of circle K with centre 0. Choose a point P exterior to K on the line through A and B and construct the tangents to K through
P, meeting K at X and Y. Let M be the intersection of AB and XY.
Prove that the tangents to K are also tangent to both the circle with centre
A and radius AM and the circle with centre B and radius BM.

Something that is true about that is that it has numbers

A. p = 2(l + w)p/2 - l = ww = p/2 - l b. while isolating the variable w in the equation, i first divided both sides by 2 and then i subtracted l from both sides. i hope this .

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: multiply exponents per exponent rules to get: remember you subtract exponents from the denominator and add exponents in the numerator so: simplify further: so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.