PLEASE HELP ME!!! Ror what values of k will the relation not be a function S={(2-|k+1|, 4), (-6, 7)}

Step-by-step explanation:

The relation S is note a function when

2 - |k+1| = -6

Because when they are equal we have two points (-6,4) and (-6,7) in S which implies that -6 is related to two different values.

Now solving

2 - |k+1| = 6

2 - |k+1| = 6

2 - 6 = |k+1|

-4 = |k +1|

But absolute value always non negative, so there is no such k.

step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: