Match each function with corresponding restrictions to its domain when p(x) = 2x and q(x) = 2x x 1. r(x) = q(x)/p(x) 2.r(x) =1/p(x)-q(x) 3.r(x) =1/p(x)+16q(x) 4.r(x) = p(x) ∘ q)(x) 5. q(x)/p(x)+2 All real numbers, no restrictions x ≠ -2 x ≠ -1 x ≠ 1, 2 x ≠ 0

b 1: 45 am

step-by-step explanation:

its that because if it was in the pm it would be 1345

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc