Part 1 of 2 O
The monthly water bill is a function of the number of gallons used. The cost is $19.50 for 20,000 gal or less. Over 20,000 gal, the cost is $19.50 plus $1 for each
1000 gal over 20,000 with any fraction of 1000 gal charged at a fraction of $1. On what interval is the cost constant? On what interval is the cost increasing?

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

it should be a and d. lmk if i'm wrong xd