If AB=2x BC=x+20 and AC=50 what is the value of x

x = 10

Step-by-step explanation:

AC = AB + BC

Substitute the values for the line segments:

50 = (2x) + (x + 20)

50 = 2x + x + 20

Combine like terms:

50 = 3x + 20

Subtract 20 from both sides:

30 = 3x

Divide both sides by 3:

10 = x

Check your work:

50 = 2(10) + 10 + 20

50 = 20 + 30

50 = 50

Correct!

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240