Ages Number of students 15-18 7 19-22 5 23-26 6 27-30 3 31-34 10 35-38 6 Based on the frequency distribution above, find the relative frequency for the class with a lower class limit of 15 Give your answer as a percent, rounded to 1 place after the decimal point, if necessary. Type only a number in the answer box (do NOT type "%" after your answer). Relative Frequency = Question Help: Message instructor Submit Question. ​

where are the choices?

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d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

b, i believe, but not sure.