10 Three points have co-ordinates A(2,6), B(8, 10) and C(6,0). The perpendicular bisector of AB meets the line BC at D. Find (i) the equation of the perpendicular bisector of AB in the form ax + by= C (ii) the co-ordinates of D.​

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

2 apples

step-by-step explanation:

taking away equals subtraction. 6-4=2

110

step-by-step explanation:

based on the question i am guessing that it is a typo for abc