Mathematics
Mathematics, 20.08.2021 01:00, jocelynbeoletto

Ive been having this question for a while "what do you use first PEMDAS or distributive property". Well you might say it doesn't matter because a problem like this 5(3+8)=x if you use PEMDAS u first add the eight and the three and you would get eleven then you times the eleven with the five to get fifty five. So x=55. If you use distributive property you would multiply the three and eight by five to get 15+40=x you would add the fifteen and the forty to get fifty five making x=55. But if you took the problem {3(525/4π)}^1/3=R then its a different situation heres the problem solved with PEMDAS.

{3(525/4π)}^1/3

{3(525/12.57)}^1/3

{3•41.77}^1/3

125.30^1/3=4.90

R=4.90

Now this is a step by step explanation on how to do distributive property.

{3(525/4π)}^1/3

(1575/12•9.40)^1/3

(1575/112.80)^1/3

13.90^1/3=2.30

R=2.30

So as you see these two equations have different answers. Now agin which of the two of them do i use distributive property or PEMDAS.

Please give a step by step explanation why i should use either or. All these problems were rounded to the nearest hundredth.

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