Mathematics, 18.08.2021 19:30, tykiabrown8111
If an object is propelled upward from a height of h feet at an initial velocity of v feet per second, then its height after t seconds is given by the equation
S= - 1612 + vt + h, where S is in feet. If the object is propelled from a height of 12 feet with an initial velocity of 64 feet per second, its height S is given by the equation
S= - 162 +64 +12.
After how many seconds is the height 40 feet?
Answers: 2
Mathematics, 21.06.2019 18:30, mauralawson
Aball is thrown from a height of 139 feet with an initial downward velocity of 15 ft/s. the ball's height h (in feet) after t seconds is given by the following. h=139-15t-16t^2 how long after the ball is thrown does it hit the ground? round your answer(s) to the nearest hundredth. (if there is more than one answer, use the "or" button.) t =
Answers: 1
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