Find x if 2 {x}^2- 3 {x} + 1 >0, where {.} denotes the fractional part in [- 1, 1]

Step-by-step explanation:

−1,

2

−1

]∪[0,

2

1

]∪{1}

For f to be defined 2{x}

2

−3{x}+1≥0

({x}−1)(2{x}−1)≥0

⇒{x}∈(−∞,

2

1

)∪[1,∞)

But we know, {x}∈[0,1)

Thus {x}∈[0,

2

1

)→(1)

Also given that x∈[−1,1]

Hence required domain is [−1,−

2

1

]∪[0,

2

1

],∪{1}

Note {−x}=1−{x}

two data sets with the same median will not have the same varaibility

step-by-step explanation: