Regroup and factorise:
x(x+2)+x+2

⇒x (x+2) + x + 2

⇒x² + 2x + x + 2

⇒x² + 3x + 2

☛ By Splitting the middle term method

⇒x² + 3x + 2

⇒x² + 2x + x + 2

⇒ x(x+2)+1(x+2)

⇒ (x+1) (x+2)

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

the line of