Find equations of the tangent plane and normal line to the surface x=3y^2+3z^2−274 at the point (-4, -9, -3). Tangent Plane: (make the coefficient of x equal to 1).

? =0

Normal line: ⟨−4, ? , ? ⟩ +t⟨1, ? , ? ⟩.

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

i would you but i don't under stand the qustion

step-by-step explanation:

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2