D) The shadow of a vertical tower on a level ground increases by 10m, when the altitude of sum changes from angle of elevation 45° to 30°. Find the height of the towe correct to one place of decimal. (Take root 3 = 1.732) Help As soon as possible please with picture please

Below.

Step-by-step explanation:

I cant draw you a picture but it will be one right triangle inside the other where the vertical tower will be one leg common to 2 triangles and the base of the 2 triangles will be x and x+10 metres.

Tan 30 = h/ (x + 10)

tan 45 = h/x        where h is the height of the tower.

From the second equation  x = h / tan45

Substituting in the first equation;

tan30 = h / (h/tan45 + 10

Tan 30 = 1/ √3 and tan 45 = 1 so

1/ 1.732 = h/ (h + 10)

0.5774 = h/(h + 10)

h = 0.5774h + 57.74

0.4226 h = 57.74

h = 136.6 m to nearest tenth.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation: