Describe how the graph of y= x2 can be transformed to the graph of the given equation. (2 points) y = x2 + 13 Shift the graph of y = x2 right 13 units. Shift the graph of y = x2 left 13 units. Shift the graph of y = x2 down 13 units. Shift the graph of y = x2 up 13 units.

1.677

step-by-step explanation:

i'm not good at explaining stuff but if you need an answer i'm here for you.

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .