Express 3x-x^2 as m-(x-n)^2. Ill give brainliest to correct answer! (Also please see the picture since you might mistake x having a square as a 2x)

This is simply done by Method of Completing the Square.

3x - x²

Add and subtract half the coefficient of x and square it.

( This is done so there'd be no alterations to the quadractic Expression)

So To start

We'd like x² to be positive...(So factor out a negative).

–(x² - 3x )

Now In this case

You see there's a Negative Outside the the bracket

Instead of adding and Subtracting squared values of half the coefficient of X... We'd Add Twice and do not subtract.

Reason: If you add outside the bracket and subtract the other inside the bracket... This will be wrong because there's a negative patiently waiting outside the bracket to Interact with the negative you subtracted to make it Positive.

See what I mean.

Let's say you added 2² and subtracted 2² in this problem

2² – ( x² - 3x - 2²)

If you decide to open the bracket

You'll have

2² – x² + 3x + 2²

NOW THIS IS WRONG BECAUSE WE ALTERED THIS EXPRESSION. WHERE'D 2² + 2² COME FROM?

THIS IS WHY YOU'LL ADD THE SQUARED COEFFICIENT OF X TWICE IN CASES LIKE THESE.

SO GOING BACK TO THE ORIGINAL QUESTION.

– (x² - 3x )

Adding the half the coefficient of x twice and squaring them...

Coefficient of x = 3

Half of 3 = 3/2

Squaring it gives (3/2)²

NOW PROCEEDING

(3/2)² – [ x² - 3x + (3/2)²]

If you open this bracket... (3/2)² will cancel out with —(3/2)²

Meaning that we haven't altered the expression in any way

Moving On...

Applying basic factorizing principle

9/4 – ( x - 3/2)².

Answer = 9/4 – ( x - 3/2)² Which is in the Form m – ( x - n )²

Therefore m = 9/4 and n = 3/2.

Hope This Helps

because 1.2 isnt half of 6 duh

the image of (6, 9) under a dilation is (4, 6). the scale factor is