Let A={1,2,3,4,5,6,7,8}A={1,2,3,4,5 ,6,7,8}. Define a relation ∼∼ on AA by a∼ba∼b if and only if 33 divides a−ba−b for all a, b∈Aa, b∈A.  1. Find all the pairs (a, b)∈A×A(a, b)∈A×A such that a∼ba∼b. 2. Show that ∼∼ is an equivalence relation on AA. 3.  Find the equivalence classes [2][2] and [3][3].​

Define relation.

Let A and B are only two non-empty set,then A*B is cartesian product of A*B.Then any subset of A*B is known as the relation fromA to B.

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3