Which points are the approximate locations of the foci of the ellipse? Round to the nearest tenth.

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

ratio is 2 : 9

the answer is three

13.5 : 3

but which class are u may know that first