If three numbers x, y, and Z are chosen at random from the interval [0, 27], what is the probability that the three numbers are a solution to the equation 2 + y + z = 27? Assure that each number in the interval is likely to be chosen with the same probability, and you can choose the same number more than once. Put your answer in decimal form with a zero before the decimal and four digits after the decimal. Round accordingly. (e. g. 0.5000 for 0.5, 0.2346 for 0.23456).