What is the expression and value of "six less than the quotient of a number and two, increased by ten" when n = 8? ​

Option 1 - StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 8.

Step-by-step explanation:

Given : Expression "six less than the quotient of a number and two, increased by ten".

To find : What is the expression and value of expression when n = 8?

Solution :

Let the number be 'n'.

The quotient of a number and two i.e. \frac{n}{2}2n

Six less than the quotient of a number and two i.e. \frac{n}{2}-62n−6

Six less than the quotient of a number and two, increased by ten i.e. \frac{n}{2}-6+102n−6+10

The required expression is \frac{n}{2}-6+102n−6+10 .

Now, when n=8,

\frac{n}{2}-6+10=\frac{8}{2}-6+102n−6+10=28−6+10

\frac{n}{2}-6+10=4-6+102n−6+10=4−6+10

\frac{n}{2}-6+10=82n−6+10=8

The value of the expression is 8.

Therefore, option 1 is correct.

StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 8.