13% of a sample of 200 students do not like ice cream. What is the 95% confidence interval to describe the total percentage of students who do not like ice cream?

The 95% confidence interval is (8.3%,17.7%), and the correct option is C.

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In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the z-score that has a p-value of .

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13% of a sample of 200 students do not like ice cream.

This means that

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95% confidence level

So , z is the value of Z that has a p-value of , so .

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The lower limit of this interval is:

The upper limit of this interval is:

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As a percentage:

Thus, the 95% confidence interval is (8.3%,17.7%), and the correct option is C.

A similar problem is given at

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

i need more info. are you looked to see there mph? how much they deliver? how far they go?

step-by-step explanation: