Mathematics, 11.08.2021 20:10, brooke1897

Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2x2 – 3x + 6, f (x)= x3 – 2x2 + 3x + 6, f (x) = x3 + 2x2 – 3x + 6, f (x) = x3 + 2x2 – 3x – 6

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answered: goldenrizo

To solve this question, we use the factor theorem, and using it, the polynomial function is:

f(x) = x^3 - 2x^2 - 3x + 6

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The factor theorem means that if k is a root of f(x), f(k) = 0.

Thus, applying the factor theorem for this question, we have to choose the function for which: $f(2) = 0, f(\sqrt{3}) = 0, f(-\sqrt{3}) = 0$

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Function 1:

f(x) = x^3 - 2x^2 - 3x + 6

Testing the values:

f(2) = 2^3 - 2(2)^2 - 3(2) + 6 = 8 - 8 - 6 + 6 = 0

$f(\sqrt{3}) = \sqrt{3^3} - 2(\sqrt{3})^2 - 3\sqrt{3} + 6 = \sqrt{3^2\times3} - 6 - 3\sqrt{3} + 6 = 3\sqrt{3} - 3\sqrt{3} = 0$

$f(-\sqrt{3}) = -\sqrt{3^3} - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 = -\sqrt{3^2\times3} - 6 + 3\sqrt{3} + 6 = -3\sqrt{3} + 3\sqrt{3} = 0$

Thus, since all three conditions are satisfied, f(x) = x^3 - 2x^2 - 3x + 6 is the polynomial function.

A similar question is given at

answered: Guest

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24 -24

-3x = -51

2nd step: divide.

-3x = -51

3 3

x = 17

hope this

answered: Guest

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