The length of a picture is 14.25 inches shorter than twice the width period if the perimeter of the picture is 133.5 inches, find its dimensions

Dimension = 27 inches by 39.75 inches

Concept:

A perimeter is a path that encompasses/surrounds/outlines a shape.

Perimeter (rectangle) = 2 (l + w)

l = length

w = width

Solve:

l = 2w - 14.25

w = w

P = 133.5

Given equation

P = 2 (l + w)

Substitute values into the equation

133.5 = 2 (2w - 14.25 + w)

Combine like terms

133.5 = 2 (3w - 14.25)

Distributive property

133.5 = 6w - 28.5

Add 28.5 on both sides

133.5 + 28.5 = 6w - 28.5 + 28.5

162 = 6w

Divide 6 on both sides

162 / 6 = 6w / 6

w = 27 in

l = 2w - 14.25 = 2 (27) - 14.25 = 39.75 in

Hope this helps!! :)

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answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

he is going to fill two shelves and the third shelf will only have five video games