The average of A and B is 6. The average of X, Y, and Z is 16. What is the average of A, B, X, Y, and Z?

12

Step-by-step explanation:

Average of A and B is 6

(A+B) /2 = 6

Multiply each side by 2

A+B = 12

average of X, Y, and Z is 16

(X+Y+Z)/3 = 16

Multiply each side by 3

(X+Y+Z) = 48

To find the average of all of them

(A+B+X+Y+Z)/5

replace A+B with 12 and X+Y+Z with 48

(12+48)/5

60/5 = 12

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.