Given three consecutive odd integers whose sum is 369, find the smallest of the three integers.

Step-by-step explanation:

369 = x + (x+2) + (x+4)

369 = 3x + 6

363 = 3x

121 = x

now that we know that x = 121, we can solve the equation by plugging in the variable

369 = x + (x+2) + (x+4)

369 = 121 + 123 + 125

369 = 369

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step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb