2sin^2(2x) + 1 = 3sin(2x) Solve for x with exact answers. The domain is 0 ≤ x ≤ π

x = π/12 and x = π/4.

Step-by-step explanation:

2sin^2(2x) + 1 = 3sin(2x)

2sin^2(2x) - 3sin(2x) + 1 = 0

(2sin(2x) - 1)(sin(2x) - 1) = 0

2sin(2x) - 1 = 0

2sin(2x) = 1

sin(2x) = 1/2

When there is a variable n = π/6, sin(π/6) = 1/2 [refer to the unit circle].

2x = π/6

x = π/12

sin(2x) - 1 = 0

sin(2x) = 1

When there is a variable n = π/2, sin(π/2) = 1 [refer to the unit circle].

2x = π/2

x = π/4

Hope this helps!

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180