Find the coefficient of the x4y2 term in the expansion of
(3x - y)
[ ? ]xy?

URGENT! Picture included

-540

Step-by-step explanation:

From binomial theorem, we can know

first term would be x^6

2nd term x^5

3rd term x^4

4th term x^3

Also, from binomial theorem, we can know

first term would be y^0

2nd term would be y^1

3rd term would be y^2

4th term would be y^3

We can see that we are looking for the 4th term (x^3y^3).

To find coefficient of 4th term, we use write:  

We can expand 6C3 using formula:    

Thus, the coefficient is -540

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option