Please help I if you can thank you do much

A. (Pay as you go) $120 B. (Regular deal) $90 C. (All-in-one price!) $100 D. The "Regular deal" option would be the least expensive for Carl.

Step-by-step explanation:

If Carl does the "Pay as you go" option he would be charged $6 each time. If he works out 20 times a month, we can multiply 20 by 6 to get a total of $120 for that option.

If Carl does the "Regular deal" option he would be charged $50 + an additional $2 for each time he works out. From there, we can get the equation 2x + 50 where x is the amount of time he works out. If we plug in 20 for x (as he works out 20 times a month), we get 2(20) + 50 which equals a total of $90 for that option.

If Carl does the "All-in-one Price!" option he would be charged $100 for the whole month meaning he has unlimited use of the gym with no extra charge besides the $100.

The cheapest option is the "Regular deal" option as it charges $90 compared to the $100 for the "All-in-one Price!" option & the $120 for the "Pay as you go" option.

126 maybe. sorry

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)