3. JK is tangent to circle L. Find JL to two decimal places.

14.32

Step-by-step explanation:

Since this is a right triangle, we can us the Pythagorean theorem

a^2 + b^2 = c^2

3^2 + 14^2 = JL ^2

9+196 = JL ^2

205 = JL ^2

Taking the square root of each side

sqrt(205) = JL

14.31782106 = JL

To 2 decimal places

14.32

answer is x<

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk