(x+1)^2=0 (x-1)^2=0
(2x-1)^2=0
(2x+3)^2=0
x^2+4x+4=0
x^2-6x+9=0
x^2+6x=-9
x^2-1=0
x^2-4=0
x^2-11=0

David estimated he had about 20 fish in his pond. a year later, there were about 1.5 times as many fish. the year after that, the number of fish increased by a factor of 1.5 again. the number of fish is modeled by f(x)=20(1.5)^x. create a question you could ask that could be answered only by graphing or using a logarithm.